[sumeet]

hi
I am running kodi (isengard) on raspberry pi b+.
I managed to associate a script with a keyboard shortcut .
Keyboard shortcut runs a sth.py file which runs an shell script stored in /storage.
I want a notification dialog window to popup every time that sth.py is run .
What should I do ?

Thanks.

[ReplayHarry]

I am not a Linux expert by any means, but if you have the ability to run a python script from within your shell, then it is easy to have that script send a notification to Kodi via json.

[sumeet]

here is my keyboard.xml configured to run py script on specific key combination press

Code:

<keymap>
  <global>
    <keyboard>
      <left mod="ctrl">RunScript(special://masterprofile/keymaps/mountro.py)</left>
      <right mod="ctrl">RunScript(special://masterprofile/keymaps/mountrw.py)</right>
      <left mod="alt">subtitledelayminus</left>
      <right mod="alt">subtitledelayplus</right>
    </keyboard>
  </global>
</keymap>

Here is my python script (mountrw.py) that runs a shell script

Code:

import subprocess


try:
    subprocess.Popen('/storage/rw.sh', shell=True)
except Exception, e:

In old versions of openelec I used to do following to get notifications when the following py got executed

Code:

import subprocess
import xbmcgui

dialog = xbmcgui.Dialog()

try:
    subprocess.Popen('/storage/rw.sh', shell=True)
    dialog.notification('Title', 'some text', xbmcgui.NOTIFICATION_INFO, 5000)
except Exception, e:

Currently I am using open elec 6.0.3 kodi v15.2 (isengard) in which replacing xbmc by kodi does not work .
I tried to give details of my situation.
Thanks.

[ReplayHarry]

Looks like you are on the right track. All you have to do is execute xbmc.GUI.ShowNotification(parameters).
Lookup the above and then you can send a notification of your choice.
Here is some code I use:

PHP Code:

def sendJson(url_in,method,parameters):
        #
        results = 0
        temp_str = url_in
        xbmc = XBMC(temp_str)
        if method == notify_method:
                #xbmc.method(parameters)
                results = xbmc.GUI.ShowNotification(parameters)
                #title="Library Clean", message = "Initiated")
        else:
                if method == libscan_method:
                        if "win" in sys.platform:
                                if ip in url_in:
                                        results = xbmc.VideoLibrary.Scan(parameters)
                                else:
                                        results = xbmc.VideoLibrary.Scan()
                        else:
                                results = xbmc.VideoLibrary.Scan()
                else:
                        if method == libclean_method:
                                results = xbmc.VideoLibrary.Clean()
        if debug_it:
                print results
        return results['result'] 


[sumeet]

Two ways worked .
(1)long one
enable webserver in settings and write in shell script

#! /bin/bash
curl -u kodi:kodi -H "Content-Type: application/json" -d '{"jsonrpc":"2.0","method":"GUI.ShowNotification","params":{"title":"'"TITLE"'","message":"'"MESSAGE"'","image":"'"warning"'","displaytime":'"10000"'},"id":1}' http://127.0.0.1:80/jsonrpc

The good thing is you can run shell script in ssh session to verify . Then add its path to py file (like mountrw.py above).
I think running webserver gives extra work to CPU and consumes RAM (even when idle with no user input).

(2)short one
write in py file

import xbmc
xbmc.executebuiltin('Notification(Hello World,This is a simple example of notifications,5000,/storage/goomba.png)')

I even added a nice icon .
Wish there was a way to show bigger dialog box in center of screen.

[Spiderfish]

@sumeet 
Is there anyway to automate this:
#! /bin/bash
curl -u kodi:kodi -H "Content-Type: application/json" -d '{"jsonrpc":"2.0","method":"GUI.ShowNotification","params":{"title":"'"TITLE"'","message":"'"MESSAGE"'","image":"'"warning"'","displaytime":'"10000"'},"id":1}' http://127.0.0.1:80/jsonrpc

Like attach it with button and send it to another XBMC?

Thanks

[Spiderfish]

I made it with python script like this way:
import requests

headers = {
    'Content-Type': 'application/json',
}

data = '{"jsonrpc":"2.0","method":"GUI.ShowNotification","params":{"title":"TITLE","message":"MESSAGE","image":"warning","displaytime":10000},"id":1}'

response = requests.post('http://192.168.1.12:8080/jsonrpc', headers=headers, data=data, auth=('kodi', '1234'))


and worked..Can i do it by dialog box instead of notification?..I am going to try and get back to you 

Thanks for all here