[Need Help] Java Script forward bypass using python
#1
Hi everyone,
I am trying to get pass this java script. Please see below:

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><title>Redirect...</title></head><body>Redirecting...<form id="myfrm" method="post" action="http://myifav.com/"><input type="hidden" name="azmdb" value="azmdb" /><input type="hidden" name="vl1" value="dHJhbnNmb3JtZXJzLWRhcmstb2YtdGhlLW1vb24tMjAxMQ==" /><input type="hidden" name="vl2" value="MTgzODg=" /><noscript><input type="submit" name="submit" value="GO" /></noscript></form><script type="text/javascript">document.getElementById('myfrm').submit();</script></body></html>

If I just my browser, I get automatically forwarded to my desired page. I don't know how to use Python to get pass. Urllib is not very helpful in this case, or I am using the wrong command.

Thank you for the help.
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