[creemyv]

At the moment I have five or six external drives connected at once. To unmount the drives without shutting down the system I have to go to:

FileManager - Name of Drive - Context Menu - Remove Safely

This has to be repeated for each drive.

Is it possible to unmount all external hard drives via a Script which I can then map to Menu Button using RunScript(path.to.script)?

[wsnipex]

udisks --unmount /dev/sdXY

[creemyv]

udisks --unmount /dev/sdXY

Created a Python Script called Unmount.py contents of which are:

udisks --unmount /dev/sdXY

Then I tried to run the following, RunScript("/home/creemyv/Unmount.py") but it didn't work

Also tried this in case it was what you meant

RunScript(udisks --unmount /dev/sdXY)
RunScript("udisks --unmount /dev/sdXY")

[xecgr]

I've tried with this python script and it succeeded:

PHP Code:

from subprocess import call
import os
for media_path, mounted_drives, _filenames in os.walk('/media'):
    for mounted_drive in mounted_drives:
        call(["sudo", "umount", "%s/%s"%(media_path,mounted_drive)])
    #don't walk into subfolders
    break 


[wsnipex]

this needs special sudo rights.


@OP: you must replace /dev/sdXY with your actual device name, e.g. /dev/sdb1

[xecgr]

Default osmc installation grants sudo permission to osmc user.
Anycase, if you want to unmount ALL devices dynamically with your command, change call statement of my previous script:

call(["udisks", "--unmount", "%s/%s"%(media_path,mounted_drive)])

[wsnipex]

the OP didn't say anything about osmc. Any normal linux will ask for a password when using sudo, so this will fail when running from a script.