[james739]

Hello,

Could someone please assist with code that will enable the selection of widget 2 content only if widget 1 content is selected. Widget 3 selection will be available only if widget 2 content is selected and widget 4 available only if widget 3 content is selected.
Thanks

[james739]

image

[Hitcher]

code:
Control.IsVisible(ID_OF_PREVIOUS_CONTROL)

[james739]

code:
Control.IsVisible(ID_OF_PREVIOUS_CONTROL)

 Using this method, widgets are always displayed. Is there a way to check if the user selected any type of content for widget 1, if content is selected, then enable widget 2. 
Here is the code for widget 1:

code :


<control type="button" id="3100">

                         <description>Browse for background</description>

                        <width>1256</width>

                        <include>DefaultSettingButton</include>

                        <label>Widget 1</label>

                        <label2>$INFO[Container(211).ListItem.Property(widgetName.personalposter1)]</label2>

                    

                        <onclick>ClearProperty(WidgetVisibility,home)</onclick>

                        <onclick>SetProperty(widgetID, personalposter1)</onclick>

                        <onclick>SendClick(312)</onclick>

                        <visible>String.IsEqual(Window.Property(groupname),mainmenu)</visible>

                       

                    </control>

So, I want widget 2 to be visible only if there's content in widget 1. I tried the following in widget 2 so that if widget 1 has information, widget 2 is enabled. Unfortunately, it did not work. What are my doing wroing?

code:
<enable>$INFO[Container(211).ListItem.Property(widgetName.personalposter1)]</enable>

code:
<control type="button" id="3101">

                         <description>Browse for background</description>

                        <width>1256</width>

                        <include>DefaultSettingButton</include>

                        <label>Widget 2</label>

                        <label2>$INFO[Container(211).ListItem.Property(widgetName.personalposter2)]</label2>

                    

                        <onclick>ClearProperty(WidgetVisibility,home)</onclick>

                        <onclick>SetProperty(widgetID, personalposter2)</onclick>

                        <onclick>SendClick(312)</onclick>

                        <visible>String.IsEqual(Window.Property(groupname),mainmenu</visible>

                        <enable>$INFO[Container(211).ListItem.Property(widgetName.personalposter1)]</enable>

                       

                    </control>

[Hitcher]

There's no condition in that code.

code:
<enable>!String.IsEmpty(Container(211).ListItem.Property(widgetName.personalposter1))</enable>

[james739]

There's no condition in that code.

code:
<enable>!String.IsEmpty(Container(211).ListItem.Property(widgetName.personalposter1))</enable>

 Works beautifully! Thank you very much