[Sranshaft]

I can't seem to get $INFO[Container.ShowPlot] to work when calling it as a variable. I'm using the following variable code to call it:

Code:

<variable name="ExtendedList_Plot">
        <value condition="[Container.Content(movies) | Container.Content(tvshows) | Container.Content(episodes) | SubString(Container.FolderPath,addons,left) | SubString(Container.FolderPath,plugin,left)] + !IsEmpty(ListItem.Plot)">$INFO[ListItem.Plot]</value>
        <value condition="Container.Content(seasons)">$INFO[Container.ShowPlot]</value>
        <value condition="[SubString(Container.FolderPath,addons,left) | SubString(Container.FolderPath,plugin,left)] + IsEmpty(ListItem.Plot)">$INFO[ListItem.Property(Addon.Description)]</value>
        <value condition="Container.Content(artists) + !IsEmpty(ListItem.Property(Artist_Description))">$INFO[ListItem.Property(Artist_Description)]</value>
        <value>Description not available</value>
    </variable>

Substituting dummy text in the Container.Content(seasons) value works as it should so maybe it's not getting converted properly? With Container.ShowPlot only an empty string is returned. Any thought?

[Hitcher]

You're not using it inside a list are you?

[Sranshaft]

Yeah, its inside the list. Is there any way we can get that inside the list or do i have to use a hacky GetLabel workaround?

[jmarshall]

List Items can only take label information from the item themselves. Not from outside the item.

[Sranshaft]

List Items can only take label information from the item themselves. Not from outside the item.

I understand that now but I would have thought I'd be able to fill a label outside of the list control and use Control.GetLabel() then inside the list but that doesn't work either. Any thoughts on how I might be able to get around this restriction?

[jmarshall]

Again, it's because Control.GetLabel() is not ListItem.*

The only way to show Container.ShowPlot is outside of a list.

[Sranshaft]

Fair enough. Thanks for the info mate.